Type casting:
Type casting is used to change the variable data_type from one to another data_type temporarily for the expression.
Eg:
char c=�a�;
int i=(int)c;
in this c is converted from char to int for temporarily. It�ll give integer equivalent of that character. Small a integer value is 97(ASCII). so i=97 .
#include < stdio.h >
void main()
{
int i;
char a[5]=�selva�;
for(i=0;i<5;i++)
{
printf(�%c�,((char*)i[&a]);
}
}
Output:
Selva
How?
Are you amaze with the output ?
i is an integer value using type casting we can convert it into another data type.
Here ((char*)i) will convert i into character pointer. In square brackets address of
a is given. This will make ((char*i)[&a] is point to ith place of string a.
consider a starting address is 1000 then characters will store in a string like this
| 1000 | 1001 | 1002 | 1003 | 1004 |
| s | e | l | v | a |
| a[0] | a[1] | a[2] | a[3] | a[4] |
in for loop at first i=0, &a=1000
((char*)i[&a] will point to 0th place of 1000.
and It�ll print s
now i�ll increase i=1,&a=1000
((char*)i[&a] will point to 1th place of 1000.
And it�ll print e
Now I�ll increase i=2,&a=1000
((char*a)i[&a] will point to 2th place of 1000
So It�ll print l
now i=3,&a=1000
((char*a)i[&a] will point to 3rd place of 1000
So it�ll print v
Now i=4,&a=1000
((char*a)i[&a] will print 4th place of 1000.
So it�ll print a.
